What does it mean to find the domain of a function defined by an equation?
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Finding the domain of a function means determining all possible input values (usually x-values) for which the function is defined and produces a real output.
How do you find the domain of a function with a square root, such as f(x) = √(x - 3)?
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For square root functions, the expression inside the root must be greater than or equal to zero. So, solve x - 3 ≥ 0, which gives x ≥ 3. Therefore, the domain is [3, ∞).
What is the domain of a rational function like f(x) = 1/(x^2 - 4)?
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For rational functions, the denominator cannot be zero. Set x^2 - 4 ≠ 0, which means x ≠ ±2. Thus, the domain is all real numbers except x = 2 and x = -2.
How do you determine the domain when the function involves a logarithm, such as f(x) = log(x - 5)?
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The argument of the logarithm must be greater than zero. So, solve x - 5 > 0, which gives x > 5. The domain is (5, ∞).
What steps should you take to find the domain of a function defined by a fraction and a square root, like f(x) = √(x - 1)/(x - 3)?
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First, ensure the expression inside the square root is ≥ 0: x - 1 ≥ 0 ⇒ x ≥ 1. Second, ensure the denominator is not zero: x - 3 ≠ 0 ⇒ x ≠ 3. Combining these, the domain is [1, 3) ∪ (3, ∞).
Can the domain of a function ever be all real numbers?
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Yes, if the function is defined for every real number without restrictions, such as f(x) = 2x + 5, then its domain is all real numbers, (-∞, ∞).
How do you find the domain of a function involving even roots with variables in the denominator, like f(x) = 1/√(x + 2)?
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Since the denominator cannot be zero and the expression inside the square root must be positive (not zero because denominator), solve x + 2 > 0 ⇒ x > -2. The domain is (-2, ∞).
What is the domain of a function defined implicitly by an equation, like x^2 + y^2 = 9 solving for y?
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When solving for y, y = ±√(9 - x^2). The expression under the square root must be ≥ 0, so 9 - x^2 ≥ 0 ⇒ -3 ≤ x ≤ 3. Therefore, the domain for x is [-3, 3].
How do you handle domain restrictions caused by absolute values in functions, such as f(x) = √(|x| - 4)?
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Set the expression inside the square root ≥ 0: |x| - 4 ≥ 0 ⇒ |x| ≥ 4. This means x ≤ -4 or x ≥ 4. So, the domain is (-∞, -4] ∪ [4, ∞).